If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x-35=-8x^2
We move all terms to the left:
6x-35-(-8x^2)=0
We get rid of parentheses
8x^2+6x-35=0
a = 8; b = 6; c = -35;
Δ = b2-4ac
Δ = 62-4·8·(-35)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-34}{2*8}=\frac{-40}{16} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+34}{2*8}=\frac{28}{16} =1+3/4 $
| 10.3=-2.5x+1.8 | | 2+3(7-x)=4 | | p+12+4=5 | | r=2r−9 | | 16w+1=-11 | | x^2+5x-6=-6 | | 9+x+36=360 | | 24(8+1-1)=4(v+1) | | 60+18x=110 | | 4x+3-9x=8 | | -2x-x=-13 | | 91=g+29 | | x^2+5x+1=-7 | | 24(8(1))=4(v+1) | | 3e+(2–4e)=- | | 5(2x-4)=45 | | 6x+6+64+12x+4=180 | | −4/3x=36 | | 3b+-5b=0 | | -120+13x=8x+40 | | (12/3x)x=62/3 | | (2v+8)/4=(v-6)/6, | | −43x=36 | | 8+w=27 | | Y+x=160 | | H=204t-16t^2 | | 49=100k^2 | | 24(8)=4(v+1) | | 3(x-7)=5x(x-1)-4 | | 7p+2(-7p-6)=-103+6p | | 4/x=12/30 | | b4+ 4=8 |